question: a bullet of mass 10g moving with velocity of 400 m/s gets embedded in a freely suspended wooden block of mass 900g.What is the velocity acquired द्वारा the block?

the first person who gives the right answer with reasons would get 100 प्रॉप्स and the others would get 40 प्रॉप्स for participating! so good luck!
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6 hours!! this सवाल would get closed.
fightxd posted एक साल  से अधिक पुराना
 fightxd posted एक साल  से अधिक पुराना
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Science जवाब

demi382 said:
answer:4.4m/s
reason: let the final velocity of the bullet embedded in it be v
according to the law of conservation of momentum,
total momentum before collision = total momentum after collision
= 0.001* 400+0.9*0/0.001 + 0.9 = 4/0.91 = 400/91 = 4.4 m/s
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correct answer but i can't belive that no one answered than आप , any way congratulations!
fightxd posted एक साल  से अधिक पुराना
bahu said:
mass of bullet= 10 g = 0.01 kg
velocity of bullet=400 m/s
mass of wooden box= 900 g =0.9 kg
velocity of wooden block= ?

formula= Mb 1*Vb 1=Mb 2*Vb 2
0.01*400=0.9*Vb2
=0.01*400/0.9=4.4444444 m/s
ans=4.4 m/s
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